How many ions are present in 30.0 mL of 0.600 M Na2CO3 solution?

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How many ions are present in 30.0 mL of 0.600 M Na2CO3 solution?

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Answer 1

Answer #1

0.600mol/L * 1L/1000mL * 30.0mL = 0.018 moles of Na2CO3.

There are 3 moles of ions (2 Na+ and 1 CO3-) for each moles of Na2CO3 in solution, so triple it!

0.018x3= 0.054moles of ions, which you can multiply by avogadro's number, 6.02x10^23

3.25x10^22 ions

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Answer 2

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