In each reaction box, place the best reagent and conditions from the list below. (A reagent may be used more than once.) Hint: step 1 is conducted at -78°C.
The concept used to solve this question is formation of a ketone by the series of reactions between ester and organolithium compound to produce an alcohol and then the oxidation of the alcohol.
Organolithium reagent acts as a nucleophile, attacks the carbonyl carbon, to form an intermediate metal alkoxide salt. Acidic work up converts the metal alkoxide salt into an alcohol which is then oxidized to the carbonyl compound by an oxidizing agent.
DIBAL-H at reduces esters to corresponding aldehydes.
Aldehydes react with organolithium reagent to give either primary alcohol or secondary alcohols. The number of carbon atoms in the alcohol formed is equal to the sum carbon atoms in the carbonyl compound and the organolithium reagent.
The general formula of a organolithium reagent is , in which R is an alkyl/aryl group, is a metal. The alkyl group acts as a nucleophile.
Reaction of aldehydes with organolithium reagent followed by the hydrolysis forms an alcohol (new bond in the product).
Jones reagent is an oxidizing agent that oxidizes primary alcohol to aldehydes and secondary alcohols to ketones.
The reaction for the reduction of methyl acetate to acetaldehyde is as follows:
The reaction for the nucleophilic attack of phenyllithium on acetaldehyde to produce the alcohol is as follows:
Oxidation of alcohol produces the desired product (acetophenone).
The reaction is as follows:
Ans:The complete reaction for the conversion of the given reactant to product is as follows:
In each reaction box, place the best reagent and conditions from the list below.
In each reaction box, place the best reagent and conditions from the list below. (Some reagents may be used more than once) In each reaction box, place the best reagent and conditions from the list below. (Some reagents may be used more than once.)
In each reaction box, place the best reagent and conditions from the list below (A reagent may be used more than once.)
In each reaction box, place the best reagent and conditions from the list below. (A reagent may be used more than once.)
In each reaction box, place the best reagent and conditions from the list below. (Some reagents may be used more than once.)
In each reaction box, place the best reagent and conditions from the list below. (Some reagents may be used more than once.)
In each reaction box, place the best reagent and conditions from the list below. A reagent may be used more than once.) Alkylating with ethyl bromide in steps 2 and 4 will lengthen the alkyne by two carbons at both ends but will not introduce the primary alcohol functional group.
In each reaction box, place the best reagent and conditions from the list below. (A reagent may be used more than once.)
In each reaction box, place the best reagent and conditions from the list below. A reagent may be used more than once.) Each end of the alkyne chain must be lengthened by two carbon atoms. Propyl bromide in step 2 would add three carbons to one end. 1) 2) CHsCH-CH-Br NaNH2 он NaNH2 3) 4) 5) H3O CH3CH2Br CH3Br CH3CH2CH2Br BH3/THF NaOH NaBH4 H2, Lindlar catalyst H3O H202/NaOH CH3CH2CH2CH2Br NaNH2
In each reaction box, place the best reagent and conditions from the list below. Please give a brief explanation for your response so I can understand it better. Thanks! In each reaction box, place the best reagent and conditions from the list below. (A reagent may be used more than once.) CH3CH2Br NaOH H2O2/NaOH H30+ CH3br NaBH4 NaNH2 CH3CH2CH2CH2Br CH3CH2CH2Br H2, Lindlar catalyst BH3/THF
In each reaction box, place the best reagent and conditions from the list below. 3-Hexanone should be the exclusive final product. (A reagent may be used more than once.)