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How many grams of Li3N can be formed from 1.75 moles of Li? Assume an excess...

How many grams of Li3N can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li(s) + N2(g) → 2 Li3N(s)

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Answer #1

Given equation: 6L1(s) + N , (g) → 2Li,N(s) 1.75 mole Number of moles of Li of moles of Li,N is produced-1 2moleLi,N 6moleLi

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