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Two samples of calcium fluoride are decomposed into their constituent elements. The first sample produced 0.154...

Two samples of calcium fluoride are decomposed into their constituent elements. The first sample produced 0.154 g of calcium and 0.146 g of fluorine. If the second sample produced 294 mg of fluorine, how many g of calcium were formed?

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Answer #1

CaF2 ---> Ca + F2

Since 1 mole of caF2 produces 1 mole each of Ca & F2

So the ration of weigths of Ca & F2 formed are equal

therefore,

[mass of Ca formed in the first sample / mass of Ca formed in the second sample] = [mass of F2 formed in the first sample / mass of F2 formed in the second sample]

=> 0.154 g / mass of Ca formed in the second sample = 0.146 g / 0.294 g

So mass of Ca formed in the second sample = (0.154/0.146)*0.294 = 0.310 g

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