Two samples of calcium fluoride are decomposed into their constituent elements. The first sample produced 0.154 g of calcium and 0.146 g of fluorine. If the second sample produced 294 mg of fluorine, how many g of calcium were formed?
CaF2 ---> Ca + F2
Since 1 mole of caF2 produces 1 mole each of Ca & F2
So the ration of weigths of Ca & F2 formed are equal
therefore,
[mass of Ca formed in the first sample / mass of Ca formed in the second sample] = [mass of F2 formed in the first sample / mass of F2 formed in the second sample]
=> 0.154 g / mass of Ca formed in the second sample = 0.146 g / 0.294 g
So mass of Ca formed in the second sample = (0.154/0.146)*0.294 = 0.310 g
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