Question

determine the theoretical yield in H2S (in moles) of 16 mol Al2S3 and 16 mol H2O...

determine the theoretical yield in H2S (in moles) of 16 mol Al2S3 and 16 mol H2O are reacted according to the following balanced reaction. A possibly useful molar mass is Al2S3 = 150.17g/mol.

Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g)

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Answer #1

Al2S3 is in excess, thus the quantity of H2O (limiting reagent) will be used for calculation.

Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g)

……………..6 moles…………………………3 moles

……………..16 moles………………………..x

x= 8 moles H2S (theoretical yield)

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