Question 6 (2 points) Determine the theoretical yield of HCl (in moles) if 0.50 mol of...
Determine the quantity of excess reactant (in moles) that remains after a reaction if 0.50 mol of BCI3 and 2.1 mol of H20 are reacted according to the following balanced reaction. Assume that the reaction goes to completion BCI3(g) +3 H20() H3BO3(s)+3 HCl(g) 1.6 mol 0.60 mol 1.5 mol 2.1 mol 0.2
Question 2 4 pts Determine the theoretical yield of HCl if 60.0 g of BCl3 and 37.5 g of H20 are reacted according to the following balanced reaction. BC13(g) + 3 H2O(1) H3BO3(s) + 3 HCl(g) 75.9 g 132g 187 g 56.0 g 25.3 g
Determine the theoretical yield of H3BO3 if 25.0 g of BC13 and 10.0 g of H20 are reacted according to the following balanced reaction. (molar masses: BC13 = 117.16 g/mol; H20 = 18.02 g/mol, H3BO3 = 61.84 g/mol; HCI - 36.46 g/mol) BC13(8) + 3 H2011) - H3BO3(s) + 3 HCl(g) 13.19 g O 34,318 O 56.08 O 11.448
Determine the theoretical yield of HCl if 60.0 g of BCl3 and 37.5 g of H2O are reacted according to the following balanced reaction. A possibly useful molar mass is BCl3 = 117.16 g/mol. BCl3(g) + 3 H2O(l) ? H3BO3(s) + 3HCl(g) I know how to do the math. So Please explain: How do I know which is the limiting reactan
determine the theoretical yield in H2S (in moles) of 16 mol Al2S3 and 16 mol H2O are reacted according to the following balanced reaction. A possibly useful molar mass is Al2S3 = 150.17g/mol. Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g)
Chemical Quantities and Aqueous Reactions 4. Determine the theoretical yield of H2S (in moles) if 32 mol Al2S3 and 32 mol H20 are reacted according to the following balanced reaction A1283(s) + 6 H2O() ? 2 Al(OH)3(s) + 3 H2S(g) A) 96 mol H2S B) 32 mol H2S C) 64 mol H2s D) 48 mol H2S E) 16 mol H2S
STUDY GUIDE - MOLES Here to determine how much Xeo, forms, simply convert the 0.0412 mol Xeos the XeF. reacting, into grams: 0.0412 mol Xerox 1708XO - 7.37 g Xeos 7) The amount of the excess reactant, water, reacted can be calculated from 0.0412 mol XeF: 12 mol Xco, formed by all of The remaining excess water is be calculated from the limiting reactant, 0.0412 mel Xerx 3 mol H20 18.02 -221 H2O (reacted) 1 mol Xer, * 1 molde...
Determine the theoretical yield of H2S (in grams) if 76.0 g Al2S3 and 53.0 g H2O are reacted according to the following balanced reaction. Identify the limiting reactant. Al2S3 (s) + 6H2O (l) ---> 2 Al(OH)3 (s) + 3 H2S (g)
Determine the theoretical yield of H2S (in moles) if 4.0 molAl2S3 and 4.0 mol H2O are reacted according to the followingbalanced reaction. A possibly useful molarmass is Al2S3 =150.17Al2S3(s)+6H2O(l)-->2Al(OH)3(s)+3H2S(g)
If the original solution contained 0.12 mol HCI, what amount of HCl, in moles, will remain when the reaction is complete? 1.4 g Zn reacted. mol resubmit Incorrect The balanced equation for the reaction is Zn +2 HCI - ZnCl2 + H2 Determine the moles of HCl required for reaction with 1.4 g Zn and subtract that amount from the mol of HCI available