Determine the theoretical yield of H2S (in grams) if 76.0 g Al2S3 and 53.0 g H2O are reacted according to the following balanced reaction. Identify the limiting reactant.
Al2S3 (s) + 6H2O (l) ---> 2 Al(OH)3 (s) + 3 H2S (g)
Determine the theoretical yield of H2S (in grams) if 76.0 g Al2S3 and 53.0 g H2O...
determine the theoretical yield in H2S (in moles) of 16 mol Al2S3 and 16 mol H2O are reacted according to the following balanced reaction. A possibly useful molar mass is Al2S3 = 150.17g/mol. Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g)
Chemical Quantities and Aqueous Reactions 4. Determine the theoretical yield of H2S (in moles) if 32 mol Al2S3 and 32 mol H20 are reacted according to the following balanced reaction A1283(s) + 6 H2O() ? 2 Al(OH)3(s) + 3 H2S(g) A) 96 mol H2S B) 32 mol H2S C) 64 mol H2s D) 48 mol H2S E) 16 mol H2S
Determine the theoretical yield of H2S (in moles) if 4.0 molAl2S3 and 4.0 mol H2O are reacted according to the followingbalanced reaction. A possibly useful molarmass is Al2S3 =150.17Al2S3(s)+6H2O(l)-->2Al(OH)3(s)+3H2S(g)
According to the following reaction, what amount of Al2S3 remains when 20.00 g of Al2S3 and 2.00 g of H2O are reacted? A few of the molar masses are as follows: Al2S3 = 150.17 g/mol, H2O = 18.02 g/mol. Al2S3(s) + 6 H2O(l) ? 2 Al(OH)3(s) + 3 H2S(g) a)14.00 g b)8.33 g c)19.78 g d)17.22 g e)28.33 g
Determine the theoretical yield of HCl if 60.0 g of BCl3 and 37.5 g of H2O are reacted according to the following balanced reaction. A possibly useful molar mass is BCl3 = 117.16 g/mol. BCl3(g) + 3 H2O(l) ? H3BO3(s) + 3HCl(g) I know how to do the math. So Please explain: How do I know which is the limiting reactan
Consider the reaction below Al2S3(s) + H2O(l) → Al(OH)3(s) + H2S(g) If 15.0g of aluminum sulfide and 10.0g of water are allowed to react as above, and assuming a complete reaction a. by calculation, find out which is the limiting reagent. b. calculate the maximum mass of H2S which can be formed from these reagents. c. calculate the mass of excess reagent remaining after the reaction is complete.
Question 6 (2 points) Determine the theoretical yield of HCl (in moles) if 0.50 mol of BCl3 and 2.1 mol of H20 are reacted according to the following balanced reaction. BC13(g) + 3 H2O(l) → H3BO3(s) + 3 HCl(g) O 1.5 mol O2.1 mol 0 0.70 0 0.17 O 0.5 Question 7 (2 points) Determine the quantity of excess reactant (in moles) that remains after a reaction if 0.50 mol of BCl3 and 2.1 mol of H20 are reacted according...
Calculate the maximum numbers of moles and grams of H2S that can form when 153.0 g of aluminum sulfide reacts with 143.0 g of water: Al2S3 + H2O → Al(OH)3 + H2S [unbalanced] ______ mol H2S ______ g H2S What mass of the excess reactant remains? ______ g excess reactant
3. How many grams of Alum could form (theoretical yield) when 1.00 g Al (limiting reactant) is used according to the balanced chemical equation given below? 2Al(s) + 2KOH(aq) + 4H2SO4 + 22H2O(1) ► 2KAI(SO4)2:12H2O(s) + 3H2(g)
4. What is the limiting reactant, theoretical yield, and % yield of iron metal (in kg) if 76.0 kg of Fe2O3 reacts with 22.1 kg of carbon to produce 42.3 kg Fe according to the following reaction: 2Fe2O3(s) + 3C(s) 4Fe(s) + 3CO2(g) Limiting Reactant - Fezoz Mass of Fe₂O₂ = 760kg Mole of Fe₂O₃ =475 grud Mass of carbon 22.1kg Mole of carbon = 1841.7 mol Theor. Yield =53.12 kg % Yield = 79.7%