Three capacitors of capacitance C1=1.50 ?F, C2 =6.00 ?F, and C3=15.0 ?F are connected to a 30.0 V battery as shown in the figure.
1. Calculate the charge on C3.
2. Calculate the voltage across C1.
equivalent capacitance for C! and C2 = 1.5 + 6.0 = 7.5
for C1 C2 and C3 -> 1 / [ 1 /7.5 + 1/15 ] = 5
Q = CV ;
Q = 5 e -6 * 30 = 1.5 e -4 C <----------charge on C3 ,
voltage across C1 = Q / C = 1.5 e -4 / 8e-6 = 18.75 V <----------ans voltatge across C1
Ceq of C1 C2 =6+1.5=7.5 microF
Ceq' of Ceq and C3=7.5*15/(7.5+15)= 5micro F
So total charge =30*5=150 microC
So charge on c3=2/3*150=100 micro coulomb
V along c1=30/3=10 volts
a)
equivalent capacitance for C! and C2 = 1.5 + 6.0 = 7.5*10^-6
for C1 C2 and C3 -> 1 / [ 1 /7.5 + 1/15 ] = 5*10^-6
Q = CV ;
Q = 5*10^-6 * 30 = 1.5*10^- 4 C
b)
voltage across C1 = Q / C = 1.5*10^ -4 / 7.5*10^-6 = 20 V
Three capacitors of capacitance C1=1.50 ?F,C2 =6.00 ?F, and C3=15.0 ?F are connected toa...
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