Question

Suppose a roulette wheel is spinning at 2.0 rev/s. 1) How long will it take for the wheel to come to rest if it experiences an angular acceleration of − 0.06 rad/s2? (Express your answer to two significant figures.)

Answer 1

Use the kinematic equation in rotational motion as

Wf = Wo +(Alpha) * t

where t is time = ?

here

Wo is initial angular velocity = 0

Wf = final angular velcoity = 2 rev/s

alse 1 rev/s = 2pi radians/s

Wf = 2*2pi = 4pi rad/s

angulr accleration (Alpha) = -0.06 rad/s^2

so

4pi = 0 - 0.06 * t

t = 209.34 secs