To move a large crate across a rough floor, you push on it with a force...

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Question

To move a large crate across a rough floor, you push on it with a force...

To move a large crate across a rough floor, you push on it with a force F at an angle of 21 ∘ below the horizontal, as shown in the figure.(Figure 1)

Part A

Find the acceleration of the crate if the applied force is 380 N , the mass of the crate is 32 kgand the coefficient of kinetic friction is 0.30.

Express your answer using two significant figures.

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Answer 1

Answer #1

m = 32 kg, F = 380 N

mu = 0.3, theta = 21 deg

From newtons 2nd law

F_n = m g + F sin theta

= 32 * 9.8 + (380 * sin 21) = 449.77 N

frictional force = mu F_n = 0.3 * 449.77 = 134.9 N

a = [F cos theta - f ] / m

= [380 cos 21 - 134.9] / 32

acceleration a = 6.87 m/s²

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Answer 2

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