Question

Suppose you have to move a heavy crate of weight 875 N by sliding it along a horizontal concrete floor. You push the cr...

Suppose you have to move a heavy crate of weight 875 N by sliding it along a horizontal concrete floor. You push the crate to the right with a horizontal force of magnitude 300 N, but friction prevents the crate from sliding.

Part A

Draw a free-body diagram of the crate.

Part B

What is the magnitude Fp of the minimum force you need to exert on the crate to make it start sliding along the floor? Let the coefficient of static friction ?s between the crate and the floor be 0.56 and that of kinetic friction, ?k, be 0.47.

Express your answer numerically in newtons to three significant figures.

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Answer #1
Concepts and reason

The concept used to solve this problem friction force.

Initially, draw the free body diagram on the crate at equilibrium.

Finally, use the normal force and the coefficient of kinetic friction to find the force acting on the crate.

Fundamentals

The expression for the magnitude of the minimum kinetic force is,

Fp =

Here, is the coefficient of kinetic friction, is the normal force acting on the object.

(A)

The free body diagram acting on the crate is,

CRATE
Fpt
mg

(B)

The expression for the friction force is,

Fp = HkN

Substitute for and 875 N
for.

Fp = 0.47x875
= 411N

Ans: Part A

The free body diagram for the crate is,

CRATE
Fpt
mg

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