A force acting on an object moving along the x axis is given by Fx = (14x - 3.0x2) N where x is in m. How much work is done by this force as the object moves from x = -1 m to x = +2 m?
+12J
+42J
+32J
+28J
-12J
A force acting on an object moving along the x axis is given by Fx =...
A force acting on an object moving along the x axis is given by Fx = (3.0 – x) N where x is in m. Calculate the work done by the force when the object moves from x = 1.0m to x = 3.0m.
The only force acting on a 1.8-kg body as it moves along the x axis is given by Fx = -(3.0x) N, where x is in m. If the velocity of the body at x = 0 is vx = +8.0 m/s, at what value of x will the body have a velocity of +4.0 m/s?
The only force acting on a 1.0-kg object moving along the x axis is shown. If the velocity Vx is +2.0 m/s at t= 0, what is the velocity at t = 4.0 s? F. (N) 16 8 0 +(s) 21-3.1.4 -8 +6.0 m/s +5.0 m/s +2.0 m/s +4.0 m/s +7.0 m/s
The only force acting on a 2.0 kg object moving along the x axis is shown. If the velocity vx is -2.0 m/s at t = 0, what is the velocity in m/s at t = 3.0s?a. -2.0b. -4,0c. -3.0d. +1.0e. -5.0
The force on aparticle, acting along the x axis, varies as shown in the figure.(a) Determine the work done by this force to move the particle along the x axisfrom x = 0.0 to x = 4.0 m.1 J(b) Determine the work done by this force to move the particle along the x axisfrom x = 0.0 to x = 15.0 m.2 J
The only force acting on a 2.6 kg body as it moves along the positive x axis has an x component Fx = −7x N, where x is in meters. The velocity of the body at x = 3.0 m is 8.2m/s. The only force acting on a 2.6 kg body as it moves along the positive x axis has an x component Fx =-7x N, where x is in meters. The velocity of the body at x = 3.0 m...
The only force acting on a 2.0-kg object moving along the x axis is shown. If the velocity Vx is +2.0 m/s at t = 0, what is the velocity at t = 4.0 s? +6.0 m/s +2.0 m/s +7.0 m/s +5.0 m/s +4.0 m/s
A force acting on a particle moving in the x-y plane is given by F=2yi+x^2j N, where x and y are in meters. The particle moves from the origin to a final position having the coordinates x=5 m and y=5 m and shown in the figure above. Calculate the work done by F along (a) OAC, (b) OBC, and (c) OC. (d) Is F a conservative or non-conservative force? Explain?
The force on a particle is directed along an x axis and given by F = F0(x/x0 - 1) where x is in meters and F is in Newtons. If F0 = 1.6 N and x0 = 2.0 m, find the work done by the force in moving the particle from x = 0 to x = 2x0 m.
The force acting on an object is given by Fy = (4x – 8) N, where x is in meters. (a) Choose the plot that best describes the force versus x from x = 0 to x = 3.00 m. F, (N) 20+ Fx (N) 20+ 104 IL x (m) 0,5 10 15 20 25 30 0,5 Lux (m) 10 15 20 25 30 -207 -20+ Fx (N) F(N) 20+ 207 101 x (m) Lux (m) 10 15 20 25...