Question

The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 90.0 kg and length L = 5.20 m is supported by two vertical massless strings. String A is attached at a distance d = 1.90 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3000 kg is supported by the crane at a distance x = 5.00 m from the left end of the bar.

Figure 1 of 1 String A m2 . String B 7

Part A: Find TATA, the tension in string A.

Part B: Find TB, the magnitude of the tension in string B.

Answer 1

Soon: m = 9oke, L=5.20m TA d = 1.90m, My=3000kg, d a=sm mag 1/2 (A) Taking torque at point B. Tad = m. g 1 + maga 1.90 TA - 90x9.8*2.6 +3000x 9,8x5 1.90 TA = 149293.2 TA = 785 75.37N B From FBD: TA=TB + mg + mag To=78575.37 - 190 +3000)x9.8 TB=48293.37N