Question

A grindstone spinning at a rate of 8.3 rev/s has what approximate angular speed

Answer 1

1)

As the velocity remains constant and the motion is circular, so -

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So, option (c) is correct.

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2)

$\omega = 8.3 \: rev/sec = \frac{8.3 \times 2\pi\:\: rad}{sec} = 52.15 \:\: rad/sec$

So, option (c) is correct.

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3)

Angular acceleration is -

$\alpha = \frac{\omega_{f} - \omega_{i}}{\Delta t} = \frac{11-2}{5.5} = 1.6364 \:\: rad/sec^2$

So, option (c) is correct.

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