The magnetic field perpendicular to a single 18.8 cm -diameter circular loop of copper wire decreases uniformly from 0.610 T to zero.
If the wire is 2.20 mm in diameter, how much charge moves past a point in the coil during this operation?
Length of wire
L = 2 pi R = 2* 3.14* 9.4*10^-2
L = 0.59 m
Resistance of wire
R = rho* L/A
R = 1.72*10^-8* 0.59 / ( 3.14* (1.1*10^-3)^2)
R = 2.671*10^-3 ohm
Induced emf is given by
e = A B / t
Current corresponding to the above induced emf
I = e/R
I = AB / (Rt)
It = AB / R
Q = AB /R = 3.14* (9.4*10^-2)^2 * 0.61 / (2.671*10^-3)
Q = 6.336 C
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The magnetic field perpendicular to a single 18.8 cm -diameter circular loop of copper wire decre...
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