Question

A 10-lb box is sliding over a rough surface (Uk=0.15) with a velocity of 10 ft/s and at the given instant the box is 5 ft away from the plate. The plate is smooth, weights 5 lb and is supported by an unstretched spring of stiffness 400 lb/ft. If the coefficient of restitution between the box and the plate is 0.6, determine the following: a. Velocity of the box just before hitting the plate. b. Velocity of the plate after being hit by the box. c. Maximum compression in the spring Box-A mom from wall koff

Answer 1

o wbort to Given That Tube weight of B Bon=l0lb. mbon g g weiglet of plate zien 5lb mass og prate map = 5 e=0.6 k = loveblyg l; = 0.15 ; U = 10ft/sec. de distance between Bon and platea sft we knows g = 32.17 Itseet FBDI a NEW=_lodb 0.15210 T=1-5l de acceleration. = a = f Box 1W + f=lik Lbxg MA =a=0-15g. d=5 ft. we know that V²-ue=gad v² (19) 2 = -2X0.15gx5 v= 100- 2x5x0.5x32-17. a) Auswer LV- 7.19 th sect bon b2 e = Vplate)fine V porotelfinet Voorly indy [box] initial plate) final 0.6= Vet-Vbg 7.79-0

e Upg - Vog 4-316 final fined cousevahen of angulen Momentum - by Votin biant hiplate "platzimming molbe tmp uprave slo 10.7.19170 -Erbs g g Vogt & of Subtracting exh @ =10 +5V VAF of 14.38 6) 3 Vbf = 10.063 - Voj 3.354 4-316 +3-315 7. 67ft/ b) prate final /geC. Auswe, ©). Maging compression takes place tohen veleeing of plate will become zero Applying Energy conservations con in Spring = x set compression More Ik x² q Hoo F447-6932_400x22 [email protected] ft = 0-0907 in. OR auswei