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4. For the reaction A + B + C the rate equation is: rate = k[A]?[B] if the concentration of A is doubled and the concentratio
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Answer #1

A+B ---> C

given

intitial Rate, R1 = K[A]^2[B]

when A becomes 2A, and B becomes 2B

final rate R2 = K[2*A]^2 [2*B] = 2^2*2 K[A]^2[B] =8*K[A]^2[B]
that means R2 = 8R1
hence whe A and B doubled, rate will become 8 times faster

Answer
C :: 8
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