Question

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A San Francisco cable car is pulled by a cable running under the street. The cable moves at a constant speed of 9.50 mi/hr. The person who operates the cable car (called a gripman) operates a grip that grabs hold of the moving cable. (See Figure 2.) The gripman can allow the cable to slide through the grip so that the car can move at a speed that is slower than the cable. In Figure 2 the cable is moving to the right. (Take this as the direction of the +x axis.) 3. Grip Figure 2 A cable car is traveling along a horizontal street at 9.50 mi/hr when the gripman sees tourists waiting at the next stop. At-0 he releases the cable and applies the brakes so that the cable car comes to rest with a constant acceleration. The cable car travels a distance of 50.0 ft while coming to rest. The cable car remains at rest at the stop for 100 seconds while passengers board and disembark. The gripman then rings the bell and reacquires the cable, allowing it to slip through the grip until the cable car achieves, with constant acceleration, a speed of 9.50 mi/hr in 10.0 seconds. a. Convert 9.50 mi/hr to f/s. (Hint: Use the conversion factor 60 mi/hr 88 f/s.) (6 points) b. What is the cable car's acceleration during the first 50.0 ft of its motion? (Watch signs.) (6 points) c. How long did it take the cable car to stop? (8 points) d. How far did the cable car travel after it left the siop and acquired a speed of 9.50 mi/hr? (6 points) e. Sketch a velocity versus time graph of the cable car's motion described in this problem. (6 points) f. Use geometry to find the area under the velocity versus time graph you made in part e. What is significance of your answer? Give the correct units. Show work. (8 points) g. (Extra Credit) Find the total length of cable that passed through the grip from when the gripman first released the cable to when the cable car reacquired a speed of 9.50 mi/hr. (6 points)

Answer 1