Question

DATA The sports car has a weight of 2,300 lbf V The friction of the car's tires with the road is ? The sports car goes through 0.4 1. o o o A rectilinear motion from A to B A curvilinear motion between B and D A rectilinear motion from D to F A sports car starts from rest going up a hill from point A to point C with a constant acceleration and reaches a speed of Vc 40 ft/s at point C. The vehicle goes from point C to point D at a constant speed. At point D the car applies the brakes until it reaches point E (before touching the spring) The car hits the spring at point E (once the car hits the spring, the driver stops applying the brakes) and compresses the spring until the vehicle stops. 2. 3. 4. 5. Y(x) 3011-(x2/6000)] SAc 120ft Sc 10 ft 150ft Sp 20 ft INCLINATION AT POINT C 11° 16° 13 Xc 20 ft Figure 1 QUESTIONS Points question 1. Calculate the acceleration and the force required to move the car up the hill while it pt goes from point A to point B.

Answer 1

Force required to move the car up the hill

we need to resolve the weight into its component

we get, mgsin(theta) along the hill and mgcos(theta) perpendicular to hill

so we need a force which overcomes frictional force and force due to gravity

F = mgsin(theta) + uF_n

F = mgsin(theta) + umgcos(theta)

F = 2300*sin13 + 0.4*2300*cos 13

F = 517.39 + 896.42

F = 1413.8 lbf is required

Now, use newton's second law to find the acceleration ,

F = ma

remember to find mass from given weight as

m = w/g = 2300 / 32.174

m = 71.486 lbm