we know,
the area under the velocity time graph shows the distance moved,
the total distance travelled = 21m = area under the graph
area under the graph = area of the trapezium = 1/2 * (sum of parallel side) * height
= 1/2 (2+8) * V = 5V
hence 5V = 21
hence V= 4.2 m/s
for PART A
the distance cover = area of first triangle = 1/2 * 4 * 4.2 =8.4 m
PART B
the distance cover = area of second triangle = 1/2 * 2 * 4.2
=4.2 m
PART C
already calculated V = 4.2 m/s
A car in stop-and-go traffic starts at rest, moves forward 21 m in 8.0 s, then...
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Randomized Variablesat = 7.8
m/s2
r = 0.29 m
ω0 = 93 rad/s
Part (a) What is the angular acceleration of
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Part (b)...
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