Its given that
fA = fB
nA v/2 La = nB v/4 Lb
Lb = nB La/2nA
nA = 2 ; nB = 3 ; La = 3.5
Lb = 3 x 3.5/(2 x 2) = 2.625 m
Hence, Lb = 2.625 m
B)f = v/4L
v at 25 deg C = 346.75 m/s
f = 346.75/(4 x 2.625) = 66.05 Hz
Hence, f = 66.05 Hz
frequen temper what could be the length of pipe B? A, which is 3.50 m long...
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