Some stove tops are smooth ceramic for easy cleaning. If the ceramic is 0.620 cm thick...
Some stove tops are smooth ceramic for easy cleaning. If the ceramic is 0.620 cm thick and heat conduction occurs through an area of 1.25 ✕ 10−2 m2 at a rate of 2271 J/s, what is the temperature difference across it (in °C)? Ceramic has the same thermal conductivity as glass and brick.
Homework Answers
Solution)
We know, Q/time=kA*deltaT/D
2271=0.84*(1.25*10^-2)*delta T/0.620*10^-2
So, delta T= 0.000745= almost neglible = 0degree C
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