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Physical Chemistry. Please show all your work. I will rate. If your answer is not b) 1KJ please explain why it is not the correct answer? Thank you in advance

3. Suppose the reaction Gibbs free energy is 1 k.J/mol, independent of temperature. The reaction enthalpy, at 50K, is equal t

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Answer #1

Answer :- (d) not enough information.

relation between ∆G , ∆H and ∆S and T

∆G = ∆H - T∆S

∆H = ∆G + T∆S

where ∆G = Gibbs free energy

T=temperature

∆S = entropy

  ∆H = enthalpy

Given from above data to find enthalpy ∆H we need to know absolute temperature , entropy , and Gibbs free energy

but entropy  ∆S is not given so we cannot calculate the enthalpy

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