Question

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Create the Born-Haber cycle and calculate the lattice energy of lithium oxide (Li2O) from the following data Quantity Ionization energy of Li(g) Electron affinity of O(g) for 2e Vaporization energy of Li(s) Bond energy of O2(g) Reaction enthalpy: 2 Li (s) + O2 Magnitude (kJ/mol) 519 603 147 499 (g) → Li20(s) a. -3081 kJ/mol b. -2586 kJ/mol c. -2205 kJ/mol d. -2972 kJ/mol e. -2831 kJ/mol The freezing point of ammonia (NH3, 17.04 g/mol) is -77.73°C. In an experiment, 367.2 grams of solid NH3 at -77.73°C is used to cool 250.0 grams of liquid NH3 from 25.00°C to the freezing point. Assume that the specific heat capacity of liquid NH3 is 4.742 J/(g . °C). What is the enthalpy of fusion of ammonia? a. 5.652 kJ/mol b.-5.652 kJ/mol c. -2.894 kJ/mol d. 0.3315 kJ/mol e. 2.894 kJ/mol

Answer 1

2Li_(s) + 1/2 O_2(g) rightarrow Li_2O_g(s) Delta H_r times n = -20 kJ/mole Delta_LE - {2 times Delta H_vap (Lis) + 1/2 times BE + O_2 + 2 times I.E of Li + ER of 0} = Delta H_r times n Delta_LE - {2 times 147 + 1/2 times 499 + 2 times 519 + 603} = -20 Delta_LE - {294 + 249.5 + 1038 + 603} = -20 Delta_LE - 76145 = -20 Delta_LE = 7594.5 kJ/mole