Question

In the figure particle 1 of charge q1-5.94q and particle 2 of charge q2 3.84q are fixed to an x axis. As a multiple of distance L, at what coordinate on the axis is the net electric field of the particles zero? 12 Number Units

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Point p where net electric field E is zero cannot be between the charges because their direction will not be opposite. So it must be beyond the charge q2 on the x axis.

Calculation is as shown below.

Let at boint P at a distance ヶ< suttan t th ey should eVual in maa-tude, be ,3.. , (L+2) NI 3 84 (L+x) on x-axis at distanee 4103 Lm onigin net field will be x : 4.103 unitsL AnsThis is ubdete to the auetion But in ajves ton it is asked that at uhat Co- ovdin ate on the ais That mean has to ine theistamee asticle miin L 4.103 L 5 1o3 L

Add a comment
Know the answer?
Add Answer to:
In the figure particle 1 of charge q1-5.94q and particle 2 of charge q2 3.84q are...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT