Question

In the figure particle 1 of charge q₁ = -7.25q and particle 2 of charge q₂ = +3.25q are fixed to an x axis. As a multiple of distance L, at what coordinate on the axis is the net electric field of the particles zero?

The answer i got the first time was WRONG!,, please get me the right answer.

Chapter 22, Problem 014 Your answer is partially correct. Try again In the figure particle 1 of charge q1 =-7.25q and particle 2 of charge q2 = +3.25q are fixed to an x axis. As a multiple of distance L, at what coordinate on the axis is the net electric field of the particles zero? 91 12 Number Units No units the tolerance is +/-2% mo the toler Click if you would like to Show Work for this question: en Show Work

Answer 1

91:- 7.254 qz P 922 3.259 L KX- 2+x electric field due to positive charge is going away from the charge and for He Negative charge it is coming towards the charge electric field at P = 0 fie E, Ez ( equal in magnitude but opposite in direction) Kq2 2 (1+x)? x² 워 (u ya 7.25 a 3.259 7.25 3.25 LEX 7.25 3.25 1.4935 1+2 x X X0.4935 x [1,4935-1] 2 20a 0,4935 3: 2.026L ther, Coordinate q P- L+x= 2.026L+2 L+x= 2.0262 +2 = 3.026L 3L