Question

Derive the integrated law for zero and second order kinetics.

Answer 1

considering Reaction - - → product Rate love 9) zero for order - Reaction :- Rate (R) = K [A] > 0 R = k K=Rate constant. for second order b) Reaction - → - Rate (R) = K[A2 Ka Rate constant. 'writing the differential Rate law expression - Rate (R) = -deal - dt R= -d[A] dt

concentration of A. For Zero order Reaction- from equation ③ & - Ki-d{A at » - dA] = + d{A] = -kat om in o both sides d[A7= 1-k dt co= concentration of a at to initially) ez = concentration of A at any time t. f dem a ak fat { flor = x 3) 1ų - 60) = -K (4-0) DO » 4-co= -kt » Kt= co-q (4= Co-kt/ ; t time

Co-kt) = for Zero ordez Reaction . TEN: $43kt For second order Reaction from equatica o & — K[A??= -dEA] at 1992 --Kat integrating beth sides - on in both sides- I dal tk dz J{A} . Co= consentration of A at to g initial concentration. concentration of 4 at to any time to cta

[A]~2 d[A] . Ik dt 1 xndx = fant n+1 TEų [A7-2+1 42+1 * . -K[27 alo 2) [429 o-k [-o] -> +inn 7 . +32 - 1 tok

ч - K+ ) – 4 = Coq kt — » Со = 4+ №4 Kt — co= q (It cokt) Cokt әре . 1+k+ . Так — «К++) co C = It cokt = for second order Reaction