Question

a metal we wel also use fusim 1 w Pose heat ice to determine in heat 8 Specific Heat of Metal Unknown Letter Mass of metal (g) Mass of water (g) (1.00 g = 1.00 mL) Z 29.55g Initial temperature of metal (°C) (Equals temperature of the boiling water) Final temperature of metal (°C) AT of metal (°C) Initial temperature of water in calorimeter (°C) 98°C 25°C 13°C 21° c 25°C 40C Final temperature of water in calorimeter (°C) AT of water (°C) Specific heat of metal (J/g °C) Supporting Calculations: T of metal TE-T,

Answer 1

Heat lost by metal = heat gained by water

i.e. -(m*C*$\Delta$T)_metal = (m*C*$\Delta$T)_water

i.e. -29.55 g * C(metal) * (25-98) ^oC = 50 g * 4.184 J/g.^oC * (25-21) ^oC

i.e. The specifi heat of the metal, i.e. C(metal) = 0.388 J/g.^oC