Question

please draw the ray diagrams for me as well

Answer 1

the thin lens equation gives image position for first lens

Q₁₌  P₁F₁ / P₁-F₁

Q₁= 30*15 / 30-15

Q₁= 30 cm

magnification by this lens M₁= - Q₁/ P₁

M₁= -30/30 = -1.00 cm

the real image formed by the first lens.

for second lens,

P₂= 20- Q₁= 20-30= -10 cm

Q₂= P₂*F₂ / P₂-F₂

Q₂= -10*15 / -10-15

Q₂= 6cm

magnification by the second lens

M₂= -Q₂ /P₂

M₂= -6/-10

M₂= 0.6 cm

virtual image is located by second lens.

the overall magnification M= M₁*M₂

M= (-1.0)*(0.6)

M= -(0.6)