Question

Part A.) An astronaut needs to measure the local gravity on a planet's moon. She decides to use a 1.5 m long pendulum. She finds it takes her pendulum 6.09 seconds to complete one full oscillation. What is the acceleration due to gravity on this moon?

-answer choices

a.) 2.1 m/s²

b.) 1.6 m/s²

c.) 1.9 m/s²

d.) 2.3 m/s²

Part B.) What is the frequency of this pendulum?

-answer choices

a.) 1.2 Hz

b.) 0.16 Hz

c.) .28 Hz

d.) 0.41 Hz

Part C.) If this pendulum were brought back to Earth, how would its frequency on Earth compare to its frequency on this moon?

-answer choices

a.) 1.2 Hz

b.) 0.28 Hz

c.) 0.41 Hz

d.) 0.16 Hz

Part D.) If the pendulum were moved from this moon to earth, Calculate the change in frequency if the mass is twice as heavy as the original.

-answer choices

a.) No change in frequency.

b.) 100% increase in frequency.

c.) 100% decrease in frequency.

d.) 50% decrease in frequency.

e.) 50% increase in frequency.

Sorry this question has so many parts. Any help is much appreciated!

Answer 1

@ Time pemod (T)2 241 4gp 6.0g = RTX 1.5 Vgp 9 p= 4+² 1.5 - 6.092 pa 1.6 m/s² ® f =yt = cea = 0.16 HZ © T = 27 4ge = 2.465 @ Falt=0.41HZ optionc Af= 0.47-076 100= Oils ! Frequency doesn't depend on mass so frequency remains same.