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question 2
Physical constants: • Planck constant h = 6.626 X 10 -34 J.S • Speed of light c = 2.998 x 108 m/s Please use the correct sign
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Answer #1

Solution:

According to equation of wavelength and Rydberg constant (RH),

1/\lambda = RH [1/n2^2 - 1/n1^2]

Where,

RH = 1.097 x 10^7  m-1

n1 = 3

n2 = 1

Therefore,

1/\lambda = 1.097 x 10^7 m-1 [ 1/(1)^2 - 1/(3)^2]

= 1.097 x 10^7 x (1/1 - 1/9) m-1

= 1.097 x 10^7 x ( 8/9) m-1

= (8.776 x 10^7 / 9) m-1

= 0.97511 x 10^7 m-1

\lambda = 1 / ( 0.97511 x 10^7) m

= 1.02553 x 10^-7 m

= 102.553 x 10^-9 m

\lambda = 102.55 nm

Frequency (v) is calculated as,

v = c/\lambda = 2.998 x 10^8 m s-1 / 1.0255 x 10^-7 m

= 2.9234 x 10^15 s-1

= 2.923 x 10^15 s-1

The value of wavelength 102.55 nm and frequency 2.923 x 10^15 s-1 belongs to UV region.

Hence, transition occurs in UV region.

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