Electrolytes are those species which when dissolved in water (or other polar solvents) can carry electricity. They do so by dissociating into cations (+ve ions) and anions (-ve ions). In the above mentioned species, Neon (Ne) cannot carry electricity because it cannot dissociate into cation and anion. Neon is a noble gas which doesn't accept electrons or donates electron and hence cannot form ion and cannot carry electricity. Rest all compounds can dissociate into water according to following reactions-
Thus, the answer will be (e) Ne
Thus
1- KOH 2- NaNO3 3- HBr 4-LiCl 5-Ne Of the species below, only is not an...
Of the species below, only is not an electrolyte. OKOH NaNO3 HBO Lici
Calculate the PH 1.) 9.55×10−2 M HBr 2.) 1.28×10−3 M KOH 3.) 8.89×10−3 M HNO3 4.) 2.54×10−4 M Sr(OH)2
Predict whether the equivalence point of each of the following titrations is below, above, or at pH= 7:1.) NaHCO3 titrated with NaOH2.) NH3 titrated with HCl3.) KOH titrated with HBr(3 seperate questions, answer choices for all 3)A.) below pH= 7B.) above pH= 7C.) at pH= 7
2 R2NBCI2 + 5 LIPH2 + 4 LiCl + 3 PH3 + Intermediate Equation la What is the maximum volume of PH3(g) that a chemist can obtain from the reaction shown by Equation 1a, if 0.005 mol LiPH reacts with 0.002 mol R NBCl, at 0°C and 1 atm? A. 0.672 mL B. 6.72 mL C. 67.2 mL D. 67.2 L
1.) A 80.0mL volume of 0.25 M HBr is titrated with 0.50 M KOH. Calculate the pH after addition of 40.0mL of KOH. 2.) Consider the titration of 50.0 mL of 0.20 M NH3 (Kb=1.8
Given the distance matrix in the table below, construct a parsimonious tree. Species 1 Species 2 Species 3 Species 4 Species 5 Species 6 Species 7 Species 1 11 18 2 19 17 3 Species 2 11 17 9 18 19 10 Species 3 18 17 -- 18 2 4 17 Species 4 2 9 18 20 5 4 Species 5 19 18 2 20 -- 7 17 Species 6 17 19 4 5 7 -- 21 Species 7 3...
I need help with 1-5 on electrolyte type, major species, and minor species 17-7 Part II. Acids and Bases in Aqueous Solution Sample Conductivity Electrolyte Type Major Species in Solution Minor Species in Solution (if applicable) 1. HC2H2O2(aq) weak 2. HCl(aq) strong 3. NaOH(aq) strong 4. NH3(aq) Week 5. HC2H2O2(aq) + NH3(aq) strong Part III. Reactions in Aqueous Solution Reactants Na2CO3(aq). H2SO4(aq) NaOH(aq) NH3(aq) Pb(CH3O2)(aq) Fe(NO3)3(aq) NH,C,H,O2(aq) H2SO4(aq)
Given the distance matrix in the table below, construct a parsimonious tree. Species 1 Species 2 Species 3 Species 4 Species 5 Species 6 Species 7 19 Species 1 18 9 17 7 8 Species 2 19 18 1 17 16 Species 3 18 4 -- 20 5 19 17 Species 4 9 18 20 16 5 Species 5 17 1 5 16 19 20 Species 6 7 17 19 5 19 2 16 Species 7 17 4 20 --...
1. Circle the one radical species below that is least thermodynamically stable. (3 pts.) Н. н" 2. Draw the structure of the major product afforded from the reaction conditions below in the box provided. (5 pts.) do HBr, H202 3. Provide the IUPAC name for the molecule below. (4 pts.) IUPAC name: 4. The AH° of any initiation step in a radical halogenation mechanism is... (3 pts.) 1) endothermic II) exothermic III) isothermic IV) isobestic V) neutral
Species 1, 2, 3, and 4 were separated using gas chromatography (species 1 is the solvent). Answer the following multiple choice question based on the chromatogram shown below. Which of the following statements are true regarding the chromatogram shown above? At t = 8 min, there is more of species 1 in the stationary phase compared to species 4. Species 4 has the highest partition coefficient. At t = 8 min, there is more of species 4 in the stationary...