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32. 2 C,H, + 13 o, - 8 co, + 10 H2O If 88 g of carbon dioxide are produced, what mass must have reacted? A) 116 g B) 14.5 g c
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Answer #1

32.

Correct option: C

Explanation:

Mass of CO2 produced = 88 g

Molar mass of CO2 = 44 g/mol

Moles of CO2 produced = mass of CO2 produced/molar mass of CO2

                                       = 88 g/44 g

                                       = 2 mol

From the balanced equation given, it is clear that 8 mol of CO2 is produced from 2 mol of butane

Therefore, 2 mol of CO2 is produced from = (2 mol x 2 mol)/8 mol = 0.5 mol of butane.

Molar mass of butane = 58.12 g/mol

Hence, the mass of butane must have reacted = 0.5 mol x 58.12 g/mol = 29 g

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