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Question: The specific heat of water is 4.18 J K and that of stainless steel is 0.51 JgK- Calculate the heat that must be sup
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1 Answer; | To find out the heat required to raise the temperatant of water and steel contain to its normal boiling of point,Now, the total heat required, -Que Qw tas - = 267.52 KJ + 30.6OKI C)3 298.19 KJ!

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