Given:
Hof(NO(g)) = 90.25 KJ/mol
Hof(H2(g)) = 0.0 KJ/mol
Hof(N2(g)) = 0.0 KJ/mol
Hof(H2O(l)) = -285.83 KJ/mol
Balanced chemical equation is:
2 NO(g) + 2 H2(g) ---> N2(g) + 2 H2O(l)
ΔHo rxn = 1*Hof(N2(g)) + 2*Hof(H2O(l)) - 2*Hof( NO(g)) - 2*Hof(H2(g))
ΔHo rxn = 1*(0.0) + 2*(-285.83) - 2*(90.25) - 2*(0.0)
ΔHo rxn = -752.16 KJ
Answer: -752.16 KJ
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