Question

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POST-LAB GUIDE QUESTIONS 1. Which among the hydrocarbons used in the experiment is/are A. saturated? B. actively unsaturated? C. aromatic? 2. Octane is an unbranched alkane of formula CeHa. Based on your observations in this experiment, predict the following: a. Solubility in water: b. Solubility in CCl: c. Combustion characteristics: d. Density versus water: 3.1-Hexene is an alkene. Based on your observations in this experiment, what should you expect to see for this compound in the following tests: a. Bromine test: b. KMnO4 test: c. Combustion: Page 5 of 30

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Answer 1

1) If, Hexane, cyclohexane, benzene, and toluene are the used compounds then we can answer questions as below: A) Hexane and cyclohexane are the saturated hydrocarbons. B) there is no actively unsaturated hydrocarbon present in the given series of compounds. C) Benzene and toluene are the aromatic compounds. 2) a) Octane is insoluble in water. b) Octane is soluble in CCI4. c) Burns with blue flame. d) Its a hydrocarbon hence it has low density as compared to water. 3) a) As 1-hexene is an alkene it should give positive Bromine test. The color should disappear. b) KMnO4: 1-hexene reacts with KMnO4 hence pink color should disappear. c) It should burn with yellow falme. 4) Hydrocarbons do have only H and C in the structure. The C-H bond is a non-polar bond and hence hydrocarbons are non-polar in nature. Thus they can not form any hydrogen bonding as well. Hence hydrocarbons do not mix in water. The hydrocarbon have less density than that of water and hence they float. 5) a) CnH2n+2 + excess 02 ---> nCO2 + (n+1)H20

b) ör-Bri: R * Br: R Br Alkene pi-electrons attacks to Br2 to give cyclic bromonium ion intermediate and then the Bromide ion attacks as a nucleophile to open the ring. 1 H4-0 OH R - RIR R in presence of H2SO4 alkene gives alcohol via carbocation intermediate. PAR d) А As shown above, alkene reacts with MnO4- to give cis diol via syn addition.