Question

3. Solve Equation 2 for V. Express your result in the form y = mx where V corresponds to y and f corresponds to x. a. Sketch (i.e., don't use data) a graph of V as a function of f. Use the back of this page for your sketch. b. What is the physical n Hal is the physical meaning of the slope of the graph you have just sketched! c. If your graph was a plot of experimer Planck's constant from its slope? was a plot of experimentally-obtained data, how would you determine a value of

equation 2 is eV = hf

Answer 1

1. The relation between frequency ($\nu$) or wavelength ($\lambda$) and the energy (E) is given by

                                  $E = h \nu = \frac{hc}{\lambda}$

where h = 6.63 x 10^-34 J.s is Planck's constant, and c = 3 x 10⁸ m/s is speed of light.

Given, the released energy is 2.6 eV.

i.e.                   E = 2.6 eV = 2.6 x 1.602 x 10^-19 = 4.165 x 10^-19 J

So, the frequency of the released radiation is

                                $\nu = \frac{4.165 \times 10^{-19}}{6.63 \times 10^{-34}} = 6.3 \times 10^{-16} \,\, Hz$

2. GIven, the wavelength of the photon is 505 nm .

So, the energy of the photon is

                                 $E = \frac{6.63 \times 10^{-19} \times 3 \times 10^{8}}{505 \times 10^{-9}} = 1.05 \times 10^{-3} \,\, J$