Given the equation: A = \frac{B}{C}
solve for c Solve for C, or rather, what is C equal to (in terms of A and B
solve for b Solve for B, or rather, What is B equal to
A = B/C
C = B/A
And B = A*C
Since A = B divided by C, C will be equal to B divided by A
and hence, B equals A multiplied by C
Given the equation: A = \frac{B}{C} solve for c Solve for C, or rather, what is...
Solve Laplace's equation, \(\frac{\partial^{2} u}{\partial x^{2}}+\frac{\partial^{2} u}{\partial y^{2}}=0,0<x<a, 0<y<b\), (see (1) in Section 12.5) for a rectangular plate subject to the given boundary conditions.$$ \begin{gathered} \left.\frac{\partial u}{\partial x}\right|_{x=0}=u(0, y), \quad u(\pi, y)=1 \\ u(x, 0)=0, \quad u(x, \pi)=0 \\ u(x, y)=\square+\sum_{n=1}^{\infty}(\square \end{gathered} $$
31) Set each equation equal to 0 then solve for t, b, and c in terms of a. Use unimodular row reduction and reorder the variables. bD + aD = t b(D+2) + a(D-1) = -c c(D+1) = a
Solve Laplace's equation on \(-\pi \leq x \leq \pi\) and \(0 \leq y \leq 1\),$$ \frac{\partial^{2} u}{\partial x^{2}}+\frac{\partial^{2} u}{\partial y^{2}}=0 $$subject to periodic boundary conditions in \(x\),$$ \begin{aligned} u(-\pi, y) &=u(\pi, y) \\ \frac{\partial u}{\partial x}(-\pi, y) &=\frac{\partial u}{\partial x}(\pi, y) \end{aligned} $$and the Dirichlet conditions in \(y\),$$ u(x, 0)=h(x), \quad u(x, 1)=0 $$
X 1.4.79 For the equation, (a) solve for x in terms of y, and (b) solve for y in terms of x 8x? - 2xy + 5y = 2 (a) Solve for x in terms of y (Use a comma to separate answers as needed. Do not factor)
Given below is the KCL equation of a circuit. Draw the circuit. \(\left[\begin{array}{ccc}1+\frac{1}{4}+\frac{1}{3} & -\frac{1}{4} & -\frac{1}{3} \\ -\frac{1}{4} & 1+\frac{1}{4}+\frac{1}{3} & -1 \\ -\frac{1}{3} & -1 & 1+\frac{1}{3}+\frac{1}{5}\end{array}\right]\left[\begin{array}{c}V_{1} \\ V_{2} \\ V_{3}\end{array}\right]=\left[\begin{array}{c}10 \\ -20 \\ 0\end{array}\right]\)
(d) Solve for p and q in terms of a, b, c, d given q-ap+b and q cp+d (e) If in the previous problem p stood for price, under what circumstances would the market clearing price (i.e. the p you solved for) be positive? (What are the restrictions on a, b, c,d that would ensure that p is positive?
2. Determine whether the given equation is exact. If it is solve the equation a)y" +xy'-y=0 b) xy" - (cosx)y' + (sin)y = 0, y>0c) x2 + xy' - y, x > 0
Solve the following matrix equation for a, b, c, and d. [a- b+c ] [ 12 1] 3d + 2a-4d10 8 d =
op-amp & capacitorplease solve this problem6. 76 Given the network in Fig. \(\mathrm{P} 6.76 .\)(a) Determine the equation for the closed-loop gain \(|\mathrm{G}|=\left|\frac{v_{0}}{v_{i}}\right|\)(b) Sketch the magnitude of the closed-loop gain as a function of frequency if \(R_{1}=1 \mathrm{k} \Omega, R_{2}=10 \mathrm{k} \Omega\), and \(C=2 \mu \mathrm{F}\).
Solve the given differential equation by separation of variables. dP/dt= P-P2 Solve the given differential equation by separation of variables. dN/dt + N = Ntet+3 Solve the given differential equation by separation of variables. Find an explicit solution of the given initial-value problem.