Question

1. A solution is made by dissolving 3.875 g of magnesium chloride in enough water to make 200.0 mL of solution. Calculate the molarity of magnesium chloride solution.

A. 0.04070 M B. 2.03510-4 M C. 0.2035 M
D. 0.3242 M
E. 8.14010-3 M

2. How many grams of Na2SO4 (MM 142.04 g/mol) are in 250. mL of a solution that has a concentration of 0.115 M?

A. 4.08 g B. 2.02 g C. 6.25 g D. 1.14 g E. 3.07 g

3. How many mL of 0.100 M Na2SO4 (MM 142.04 g/mol) are required to have a mass of 2.50 g of Na2SO4?

A. 0.176 mL B. 3551 mL C. 176 mL D. 35.51 mL E. 17.6 mL

4. If a student wishes to make 250 mL of a 3.0 M solution of HCl using stock 12.0 M HCl, how much HCl stock solution do they need to use?

A. 63 mL
B. 6.9 mL C. 0.016 mL D. 1000 mL E. 0.144 mL

5. How many grams of CaCO3 (MM 100.09 g/mol) will react with 142 mL of 0.750 M HCl (MM 36.46 g/mol)?

2HCl(aq) + CaCO3(s)  CaCl2(aq) + H2O(l) + CO2(g)

A. 5.33 g B. 37.9 g C. 2.12 g D. 14.6 g E. 1.36 g

Answer 1

mass ot Hgd 0nelaxity lo o0 X mo lar mass f Volame of the 5o leation in nl 3.&75J Melarity X s 9/mak Molarity O-2035M mass of Na, soy (000 X O-115 H= प२-०५ ऽ/a 0-115M I42-04 X250 mass of Na, so