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* A ball of mass M and radius R has a rotational inertia of · The ball is released from rest and rolls without slipping down
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Answer #1

let v is the linear speed and w is the angular speed of sphere at the bottom of the ramp.
Apply conservation of energy

final kinetic energy = initial potential energy

(1/2)*m*v^2 + (1/2)*I*w^2 = m*g*h

(1/2)*m*v^2 + (1/2)*(2/5)m*r^2*w^2 = m*g*h

(1/2)*m*v^2 + (1/5)*m*(r*w)^2 = m*g*h

(1/2)*m*v^2 + (1/5)*m*v^2 = m*g*h

(7/10)m*v^2 = m*g*h

v = sqrt(10*g*h/7)

now, y_max = v^2/(2*g)

= (10*g*h/7)/(2*g)

= (5/7)*h <<<<<<<<---------------Answer

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