I got the rate law will = as is.
![as what is the rate law? b/What is the overall order of the reaction? EXP [Haseos] [I ] [ H J Inital Rate 1 100x10 l.cunlo Z](http://img.homeworklib.com/questions/19c93a00-6f1b-11ea-9edf-03e30f07ee2a.png?x-oss-process=image/resize,w_560)
Homework Answers
Assume rate law r = k[H2SeO3]x[I-]y[H+]z
take data 4 and 5
![③ - 2.04 810-4 = K[2.00x10-2] [3x164] [8x102 2.548105 = [1x10-2] * [3X164) ² (8 x 10-22 dinde © by 20 ake data ③ & 7 6.36x10-](http://img.homeworklib.com/questions/1a718990-6f1b-11ea-ae31-61cd02efed64.png?x-oss-process=image/resize,w_560)
your answer partial orders are
correct but overall order = 2+1+3 = 6
Add Answer to:
I got the rate law will = as is.
H2SeO3 has a 3rd order of
reaction...
39) What are the units of k in the following rate law? Rate = K[X][Y]1/2 40)...
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c) What is the order in the reaction; zero order, 1st order, or 2nd order. Please...
c) What is the order in the reaction; zero order, 1st order, or
2nd order.
Please show all work, please don't just say that
Step1 From 2nd and 3rd observations [A] has doubled; [B] has
remained the same and rate hs also remained the same. Thus order
with respect to A is 0.
Step2 From 3rd and 4th observations [A] has remained same ;[B] has
become 1.5 times;
the rate has become 2.25 times. Thus order with respect to B...
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What is the overall order of the following reaction, given the rate law? X + 2Y...
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A first order irreversible reaction to convert compound X to compound Y in solution is planned...
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c) What is the order in the reaction; zero order, 1st order, or
2nd order.
Please show all work, please don't just say that
Step1 From 2nd and 3rd observations [A] has doubled; [B] has
remained the same and rate hs also remained the same. Thus order
with respect to A is 0.
Step2 From 3rd and 4th observations [A] has remained same ;[B] has
become 1.5 times;
the rate has become 2.25 times. Thus order with respect to B...
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