c) What is the order in the reaction; zero order, 1st order, or 2nd order.
Please show all work, please don't just say that
Step1 From 2nd and 3rd observations [A] has doubled; [B] has
remained the same and rate hs also remained the same. Thus order
with respect to A is 0.
Step2 From 3rd and 4th observations [A] has remained same ;[B] has
become 1.5 times;
the rate has become 2.25 times. Thus order with respect to B is
2.
when concentration of A changed alone rate does not change so with respect to A reaction is zero order
when concentration of B doubled rate increased 4 times so with respect to B reaction is second order
so rate law as follows
rate = K[B]2
so overall order = 2
for second order
t1/2 = 1 / K[B0]
so first we must find K for the reaction
K = rate / [B]2
K = 0.125 / [0.022]2 = 0.125 / 0.000484
K = 2.58 x 102 M-1s-1
t1/2 = 1 / 2.58 x 102 x 0.022
t1/2 = 1 / 5.676
t1/2 = 0.176 s
what you have shown in step 1 and step 2 is correct only
c) What is the order in the reaction; zero order, 1st order, or 2nd order. Please...
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