Question

1.
A projectile is fired up into the air at a speed of 127 m/s at an angle of 38° relative to the horizontal. Ignore air drag A.) Determine the MAXIMUM HEIGHT (above where it was thrown) the projectile will reach X Dimensionally incorrect. Please check the type or dimension of your unit B.) Determine how LONG the projectile will be in the air. Assume it lands at the same height it was launched. C.)Assuming it lands at the same height it was launched at, determine how FAR the projectile wll land from where it was launched. D.) Assuming it lands at the same height it was launched at, determine how FAST the projectile will be going upon impact. E.) Assuming it lands at the same height it was launched at, determine the ANGLE (relative to the horizontal) of impact.
2.  

Please answer both questions.

Answer 1

V = 127 m/s theta = 38 degree H_max = V^2 sm^2 theta/2g = 127^2 times (sm 38)^2/2 times 9.81 H_m = 311.6 m B) t = 2 u sm theta/g = 2 times 127 times sm 38/9.81 T = 15.94 ke c) R = u^2 sm 2 thats/g = 127^2 sm (2 times 38)/9.81 R = 1595.3 m d) V = 127 m/s (e) theta = 38 degree