Question

Constants PartA A 2.00-kg, frictionless block is attached to an ideal spring with force constant 300 N/m. Att0 the block has velocity -4.00 m/s and displacement +0.200 m Find (a) the amplitude and (b) the phase angle SubmitR Request Answer Part B rad Submit Request Answer

Answer 1

a) The angular frequency of the block is, 300 2.00 12.247rad/s The velocity of the block in Simple harmonic motion is, 4 12.247 0.3266 mm -0.327nm b) Here, the initial displacement is Hence, the displacement x A cos From the above equation, Hence, cos ф x-Asin (or+p) = (0.327 m )sin | (12.247)1+- =(0.327 m )sin! (12.2)1+ or (-0.327 m )cos(12.2t)rad/s