If the sampled population has a mean of 48 and standard deviation of 16, then the mean and the standard deviation for the sampling distribution of x-bar for n = 16 are
4 and 1
12 and 4
48 and 4
48 and 1
48 and 16
I know the answer already. please explain!
Solution :
Given that,
The sampling distribution of mean is ,
= 48
The sampling distribution of standard deviation is ,
=
/
n = 16 /
16 = 16 / 4 = 4
48 and 4
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