Question

What volume (in mL) of 0.300 M HCI would be required to completely react with 5.00 g of Al in the following chemical reaction? 2 Al(s) + 6 HCl(aq) → 2 AICI: (aq) + 3 H2 (g)

Answer 1

Balanced chemical equation is:

2 Al + 6 HCl ---> 2 AlCl3 + 3 H2

Molar mass of Al = 26.98 g/mol

mass(Al)= 5.0 g

use:

number of mol of Al,

n = mass of Al/molar mass of Al

=(5 g)/(26.98 g/mol)

= 0.1853 mol

According to balanced equation

mol of HCl reacted = (6/2)* moles of Al

= (6/2)*0.1853

= 0.556 mol

This is number of moles of HCl

use:

M = number of mol / volume in L

0.3 = 0.556/ volume in L

volume = 1.85 L

volume = 1850 mL

Answer: 1850 mL