Question

Question 9 1 pts What is the theoretical yield of iron (55.845 g/mol) when 10.0 g Fe2O3 (159.69 g/mol) reacts with excess carbon (12.01 g/mol)? 2 Fe,03()+3C(5) ► Fe(s)+300,(8) 3.50 g 57.2g 14.3g 6.99 g 1.75 g

Answer 1

2 fez 03 (8) + 30) 4 fels) + 3002 egg from this balanced chemical equation, it can be said that 2 molee of Fe2O3 reacts with 3 moles of c to produce 4 moles of fe and 3 moleo of co. ... Molee of fe = Moles of Fe2O3 xe Given- mass of moles of Fe2O3 = Fe2O3 = log massot Fez0.3 Molar mass of fe 203

0.0626 moles - log 159.6gglmol ... moles of fe produced = 0.062662 0:125 molee. e Mass of fe produced a moles of x molar fe mase produced of fe = هعمهعكههلمييهيمه . 3 0.125 mol x 55.8459 no = 6.989. sooption @ is correct.

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