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Preparation of Solutions: Pre-laboratory Assignment Instructor Name Section Date 2. Prepare a written plan for making up 100.
3. Calculate the number of moles of precipitate that would be produced when two solutions were mixed. 1.0 mL 0.10 M Pb(NOs)2
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Answer #1

The amount of KI needed = (100/1000) L * 0.1 mol/L = 0.01 mol

The molar mass of KI = 39.1 + 126.9 = 166 g/mol

Therefore, the mass of KI needed = 0.01 mol * 166 g/mol = 1.66 g

Question 2.

[CaCl2.2H2O] = [CaCl2]

M1V1 = M2V2

i.e. 2 M * V1 = 0.1 M * 100 mL

i.e. The volume of 2.0 M CaCl2.2H2O solution needed = 0.1*100/2 = 5 mL

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