We use the relation: Molarity * Volume = consyant. Now assuming an initial volume V of 2.00 M solution is diluted to 100 mL of 0.1 M solution:
2 * V = 0.1 * 100
Solving, V = 5 mL
Therefore, we take 5 mL of the 2.00 M solution and add 95 mL water to it to obtain the final solution
2. Prepare a written plan for making up 100.0 ml of a solution that is 0.100M...
1. Prepare a written plan for making up 100.0 ml of 0.100 M KI solution. (Note the list of reagents and equipment provided in the background information). Include in your plan the exact amount of KI that you will need and the actual 2. Prepare a written plan for making up 100.0 ml of a solution that is 0.100M in Ca2 ion using 2.00 M CaCl2 2H2O solution. steps that you will take to prepare the solution. This plan should...
Preparation of Solutions: Pre-laboratory Assignment Instructor Name Section Date 2. Prepare a written plan for making up 100.0 ml of a solution that is 0.100M in Ca2 ion using 2.00 M CaCl2H2O solution. 1. Prepare a written plan for making up 100.0 ml of 0.100 M KI solution. (Note the list of reagents and equipment provided in the background information). Include in your plan the exact amount of KI that you will need and the actual steps that you will...
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.240 M sodium benzoate. How much of each solution should be mixed to prepare this buffer? You need to prepare 100.0 mL of a pH-4.00 buffer solution using 0.100 M benzoic acid (pKa 4.20) and 0.240 M sodium benzoate. How much of each solution should be mixed to prepare this buffer? Number 31 mL benzoic acid Number 31 mL sodium...
how many milliliters of a stock solution of 2.00 M KNO3 would you need to prepare 100.0 mL of 0.150 M KNO3?
If I mixed 100.0 mL of a nitric acid solution of pH = 2.40 with 100.0 mL of a nitric acid solution of pH = 2.70, what would be the pH of the mixture? Write your answer to 2 digits beyond the decimal (e.g., 8.63) If 5.15 grams of iron(III) nitrate (molar mass = 241.86 g/mol) is dissolved in enough water to prepare exactly 150.0 mL of solution, what would be the molar concentration of the nitrate ion? 0.284 M...
6. How many mL of a 0.250 M KCl solution contains 34.5 g KCI? 7. To what volume (in mL) should you dilute 100.0 mL of a 2.50 M CaCl2 solution to obtain a 0.550 M CaCl2 solution?
You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100 M benzoic acid (pK. = 4.20) and 0.220 M sodium benzoate. How many milliliters of each solution should be mixed to prepare this buffer? benzoic acid: mL sodium benzoate: ml
You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.180 M sodium benzoate. How many milliliters of each solution should be mixed to prepare this buffer? benzoic acid: mL mL sodium benzoate: sodium benzoate: ml.
You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100 M benzoic acid (pK; = 4.20) and 0.240 M sodium benzoate. How many milliliters of each solution should be mixed to prepare this buffer? benzoic acid: ] mL sodium benzoate:
You need to prepare 100.0 mL of a pH=4.00 buffer solution using 0.100 M benzoic acid (pKa = 4.20) and 0.140 M sodium benzoate. How much of each solution should be mixed to prepare this buffer? mL benzoic acid = ? mL sodium benzoate = ?