Q3. A 5-cm-high, upright virtual image is produced when an object is placed 12 cm from...
An object is placed 10.0 cm in front of a lens. An upright, virtual image is formed 30.0 cm away from the lens. What is the focal length of the lens? Is the lens converging or diverging?
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position cm height cm Is the image inverted or upright? O upright inverted Is the image real or virtual? Oreal virtual
7. An object is placed 10.0 cm in front of a lens. An upright, virtual image is formed 30 cm away from the lens. (a) What is the focal length of the lens? (b) Find the magnification of the image.
An object is placed 13.5 cm in front of a lens. An upright, virtual image is formed 25.1 cm from the lens.(a) What is the magnification?(b) What is the focal length of the lens?
A small object is placed 25.0 cm from a converging lens of focal length 40.0 cm. The object is to the left of the lens. Where is the image? A- 17cm to the right of the lens B- 25cm to the left of the lens C- 17 cm to the left of the lens D-25 cm to the right of the lens E-67cm to the right of the lens F-67 cm to the left of the lens A small object...
An object 1.7 cm high is placed 41.9 cm to the left of a lens having a focal length of 28.9 cm. A) Is this lens converging or diverging? B) Find the location of the image produced by this lens. c)Is the image inverted or upright? d) What is the height of the image? (only positive numbers here, even if the image is inverted)
A converging lens with a focal length of 12 cm produces a 3-cm high virtual image of a 1-cm high object. Which entry in the table below is correct? Draw a neat ray diagram. PLEASE REMEMBER TO DRAW THE RAY DIAGRAM. Problem 13 A converging lens with a focal length of 12 cm produces a 3-cm high virtual image of a 1-cm high object. Which entry in the table below is correct? image distance location of image A) 8 cm...
2) A diverging lens is placed 20. cm away from an object, 80. cm from the diverging lens is a converging lens whose focal length is 25 cm. 35. cm from the converging lens is a screen showing an image of the object. a) What is the focal length of the diverging lens? f = 25. cm o *20. cm → 80. cm + 35 cm → b) What type of image is it? Circle one Real or Virtual c)...
What is the position of the image of a 5-cm-high object placed 25 cm from a +5.0-cm-focal-length converging lens? Draw a ray diagram. 9.